Prevent double-logging of 'timeout for updates'

telethon/_updates/messagebox.py

@@ -250,7 +250,10 @@ class MessageBox:
         elif self.next_deadline in self.map:
             deadline = min(deadline, self.map[self.next_deadline].deadline)
 
-        if now > deadline:
+        # asyncio's loop time precision only seems to be about 3 decimal places, so it's possible that
+        # we find the same number again on repeated calls. Without the "or equal" part we would log the
+        # timeout for updates several times (it also makes sense to get difference if now is the deadline).
+        if now >= deadline:
             # Check all expired entries and add them to the list that needs getting difference.
             self.getting_diff_for.update(entry for entry, gap in self.possible_gaps.items() if now > gap.deadline)
             self.getting_diff_for.update(entry for entry, state in self.map.items() if now > state.deadline)

telethon/client/updates.py

@@ -335,14 +335,16 @@ class UpdateMethods:
                     continue
 
                 deadline = self._message_box.check_deadlines()
+                deadline_delay = deadline - asyncio.get_running_loop().time()
+                if deadline_delay > 0:
+                    # Don't bother sleeping and timing out if the delay is already 0 (pollutes the logs).
                     try:
-                    updates = await asyncio.wait_for(
+                        updates = await asyncio.wait_for(self._updates_queue.get(), deadline_delay)
-                        self._updates_queue.get(),
-                        deadline - asyncio.get_running_loop().time()
-                    )
                     except asyncio.TimeoutError:
                         self._log[__name__].info('Timeout waiting for updates expired')
                         continue
+                else:
+                    continue
 
                 processed = []
                 try: