mirror of
https://github.com/LonamiWebs/Telethon.git
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209 lines
7.5 KiB
Python
209 lines
7.5 KiB
Python
"""
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Simple markdown parser which does not support nesting. Intended primarily
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for use within the library, which attempts to handle emojies correctly,
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since they seem to count as two characters and it's a bit strange.
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"""
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import re
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from ..tl import TLObject
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from ..tl.types import (
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MessageEntityBold, MessageEntityItalic, MessageEntityCode,
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MessageEntityPre, MessageEntityTextUrl
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)
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DEFAULT_DELIMITERS = {
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'**': MessageEntityBold,
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'__': MessageEntityItalic,
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'`': MessageEntityCode,
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'```': MessageEntityPre
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}
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# Regex used to match utf-16le encoded r'\[(.+?)\]\((.+?)\)',
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# reason why there's '\0' after every match-literal character.
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DEFAULT_URL_RE = re.compile(b'\\[\0(.+?)\\]\0\\(\0(.+?)\\)\0')
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# Reverse operation for DEFAULT_URL_RE. {0} for text, {1} for URL.
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DEFAULT_URL_FORMAT = '[{0}]({1})'
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# Encoding to be used
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ENC = 'utf-16le'
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def parse(message, delimiters=None, url_re=None):
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"""
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Parses the given markdown message and returns its stripped representation
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plus a list of the MessageEntity's that were found.
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:param message: the message with markdown-like syntax to be parsed.
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:param delimiters: the delimiters to be used, {delimiter: type}.
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:param url_re: the URL bytes regex to be used. Must have two groups.
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:return: a tuple consisting of (clean message, [message entities]).
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"""
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if url_re is None:
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url_re = DEFAULT_URL_RE
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elif url_re:
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if isinstance(url_re, bytes):
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url_re = re.compile(url_re)
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if not delimiters:
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if delimiters is not None:
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return message, []
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delimiters = DEFAULT_DELIMITERS
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delimiters = {k.encode(ENC): v for k, v in delimiters.items()}
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# Cannot use a for loop because we need to skip some indices
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i = 0
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result = []
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current = None
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end_delimiter = None
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# Work on byte level with the utf-16le encoding to get the offsets right.
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# The offset will just be half the index we're at.
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message = message.encode(ENC)
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while i < len(message):
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if url_re and current is None:
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# If we're not inside a previous match since Telegram doesn't allow
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# nested message entities, try matching the URL from the i'th pos.
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url_match = url_re.match(message, pos=i)
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if url_match:
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# Replace the whole match with only the inline URL text.
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message = b''.join((
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message[:url_match.start()],
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url_match.group(1),
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message[url_match.end():]
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))
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result.append(MessageEntityTextUrl(
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offset=i // 2, length=len(url_match.group(1)) // 2,
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url=url_match.group(2).decode(ENC)
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))
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i += len(url_match.group(1))
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# Next loop iteration, don't check delimiters, since
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# a new inline URL might be right after this one.
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continue
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if end_delimiter is None:
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# We're not expecting any delimiter, so check them all
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for d, m in delimiters.items():
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# Slice the string at the current i'th position to see if
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# it matches the current delimiter d, otherwise skip it.
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if message[i:i + len(d)] != d:
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continue
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if message[i + len(d):i + 2 * len(d)] == d:
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# The same delimiter can't be right afterwards, if
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# this were the case we would match empty strings
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# like `` which we don't want to.
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continue
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# Get rid of the delimiter by slicing it away
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message = message[:i] + message[i + len(d):]
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if m == MessageEntityPre:
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# Special case, also has 'lang'
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current = m(i // 2, None, '')
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else:
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current = m(i // 2, None)
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end_delimiter = d # We expect the same delimiter.
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break
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elif message[i:i + len(end_delimiter)] == end_delimiter:
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message = message[:i] + message[i + len(end_delimiter):]
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current.length = (i // 2) - current.offset
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result.append(current)
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current, end_delimiter = None, None
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# Don't increment i here as we matched a delimiter,
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# and there may be a new one right after. This is
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# different than when encountering the first delimiter,
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# as we already know there won't be the same right after.
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continue
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# Next iteration, utf-16 encoded characters need 2 bytes.
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i += 2
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# We may have found some a delimiter but not its ending pair.
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# If this is the case, we want to insert the delimiter character back.
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if current is not None:
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message = (
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message[:2 * current.offset]
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+ end_delimiter
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+ message[2 * current.offset:]
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)
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return message.decode(ENC), result
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def unparse(text, entities, delimiters=None, url_fmt=None):
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"""
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Performs the reverse operation to .parse(), effectively returning
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markdown-like syntax given a normal text and its MessageEntity's.
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:param text: the text to be reconverted into markdown.
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:param entities: the MessageEntity's applied to the text.
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:return: a markdown-like text representing the combination of both inputs.
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"""
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if not delimiters:
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if delimiters is not None:
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return text
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delimiters = DEFAULT_DELIMITERS
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if url_fmt is None:
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url_fmt = DEFAULT_URL_FORMAT
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if isinstance(entities, TLObject):
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entities = (entities,)
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else:
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entities = tuple(sorted(entities, key=lambda e: e.offset, reverse=True))
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# Reverse the delimiters, and encode them as utf16
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delimiters = {v: k.encode(ENC) for k, v in delimiters.items()}
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text = text.encode(ENC)
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for entity in entities:
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s = entity.offset * 2
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e = (entity.offset + entity.length) * 2
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delimiter = delimiters.get(type(entity), None)
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if delimiter:
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text = text[:s] + delimiter + text[s:e] + delimiter + text[e:]
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elif isinstance(entity, MessageEntityTextUrl) and url_fmt:
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# If byte-strings supported .format(), we, could have converted
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# the str url_fmt to a byte-string with the following regex:
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# re.sub(b'{\0\s*(?:([01])\0)?\s*}\0',rb'{\1}',url_fmt.encode(ENC))
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#
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# This would preserve {}, {0} and {1}.
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# Alternatively (as it's done), we can decode/encode it every time.
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text = (
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text[:s] +
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url_fmt.format(text[s:e].decode(ENC), entity.url).encode(ENC) +
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text[e:]
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)
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return text.decode(ENC)
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def get_inner_text(text, entity):
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"""
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Gets the inner text that's surrounded by the given entity or entities.
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For instance: text = 'hey!', entity = MessageEntityBold(2, 2) -> 'y!'.
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:param text: the original text.
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:param entity: the entity or entities that must be matched.
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:return: a single result or a list of the text surrounded by the entities.
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"""
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if not isinstance(entity, TLObject) and hasattr(entity, '__iter__'):
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multiple = True
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else:
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entity = [entity]
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multiple = False
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text = text.encode(ENC)
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result = []
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for e in entity:
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start = e.offset * 2
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end = (e.offset + e.length) * 2
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result.append(text[start:end].decode(ENC))
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return result if multiple else result[0]
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