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0fe0cdf682
See their #197 issue.
50 lines
1.9 KiB
Python
Executable File
50 lines
1.9 KiB
Python
Executable File
import time
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import random
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from utils import BinaryWriter, BinaryReader
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class MtProtoPlainSender:
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"""MTProto Mobile Protocol plain sender (https://core.telegram.org/mtproto/description#unencrypted-messages)"""
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def __init__(self, transport):
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self._sequence = 0
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self._time_offset = 0
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self._last_msg_id = 0
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self._transport = transport
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def send(self, data):
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"""Sends a plain packet (auth_key_id = 0) containing the given message body (data)"""
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with BinaryWriter() as writer:
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writer.write_long(0)
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writer.write_long(self.get_new_msg_id())
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writer.write_int(len(data))
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writer.write(data)
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packet = writer.get_bytes()
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self._transport.send(packet)
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def receive(self):
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"""Receives a plain packet, returning the body of the response"""
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seq, body = self._transport.receive()
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with BinaryReader(body) as reader:
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auth_key_id = reader.read_long()
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msg_id = reader.read_long()
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message_length = reader.read_int()
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response = reader.read(message_length)
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return response
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def get_new_msg_id(self):
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"""Generates a new message ID based on the current time (in ms) since epoch"""
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# See https://core.telegram.org/mtproto/description#message-identifier-msg-id
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ms_time = int(time.time() * 1000)
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new_msg_id = (((ms_time // 1000) << 32) | # "must approximately equal unixtime*2^32"
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((ms_time % 1000) << 22) | # "approximate moment in time the message was created"
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random.randint(0, 524288) << 2) # "message identifiers are divisible by 4"
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# Ensure that we always return a message ID which is higher than the previous one
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if self._last_msg_id >= new_msg_id:
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new_msg_id = self._last_msg_id + 4
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self._last_msg_id = new_msg_id
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return new_msg_id
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