encode/django-rest-framework
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small changes from pull request feedback

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This commit is contained in:
Craig Blaszczyk 2011-12-11 16:39:17 +00:00
parent 9f6d104dad
commit 3eb6fe5ad6
1 changed files with 3 additions and 9 deletions
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12
djangorestframework/builtins.py
View File

@ -1,4 +1,5 @@
from django.conf.urls.defaults import patterns, url, include from django.conf.urls.defaults import patterns, url, include
from collections import defaultdict
class ApiEntry(object): class ApiEntry(object):
""" """
@ -35,17 +36,16 @@ class ApiEntry(object):
) )
return urlpatterns return urlpatterns
@property
def urls(self): def urls(self):
return self.get_urls(), 'api', self.namespace return self.get_urls(), 'api', self.namespace
urls = property(urls)
class DjangoRestFrameworkApi(object): class DjangoRestFrameworkApi(object):
app_name = 'api' app_name = 'api'
namespace = 'api' namespace = 'api'
def __init__(self, *args, **kwargs): def __init__(self, *args, **kwargs):
self._registry = {} self._registry = defaultdict(lambda: defaultdict(list))
super(DjangoRestFrameworkApi, self).__init__(*args, **kwargs) super(DjangoRestFrameworkApi, self).__init__(*args, **kwargs)
def register(self, view, resource, namespace=None, name=None): def register(self, view, resource, namespace=None, name=None):
@ -62,12 +62,6 @@ class DjangoRestFrameworkApi(object):
name = resource.__name__.lower() name = resource.__name__.lower()
resource.api_name = name resource.api_name = name
if namespace not in self._registry:
self._registry[namespace] = {}
if name not in self._registry[namespace]:
self._registry[namespace][name] = []
api_entry = ApiEntry(resource, view, name, namespace) api_entry = ApiEntry(resource, view, name, namespace)
self._registry[namespace][name].append(api_entry) self._registry[namespace][name].append(api_entry)