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Correct 'serializer' to 'resource' in the docs

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Mjumbe Wawatu Poe 2012-09-08 16:31:36 -04:00
parent 6cd046cfdf
commit f8a1d38074
1 changed files with 5 additions and 5 deletions
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docs/tutorial/6-resource-orientated-projects.md
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@ -21,12 +21,12 @@ urls.py
urlpatterns = api.urlpatterns urlpatterns = api.urlpatterns
### Do you need a serializer at all? ### Do you need a resource at all?
In the preceding example, the `Serializer` classes don't define any custom values In the preceding example, the `Resource` classes don't define any custom values
(yet). As a result, the default model serializer will be provided. If you are (yet). As a result, the default model resource will be provided. If you are
happy with the default serializer, you don't need to define a `Serializer` happy with the default resource, you don't need to define a `Resource`
object at all -- you can register the resource without providing a `Serializer` object at all -- you can register the resource without providing a `Resource`
description. The preceding example could be simplified to: description. The preceding example could be simplified to:
from djangorestframework.routers import DefaultResourceRouter from djangorestframework.routers import DefaultResourceRouter