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96 lines
3.2 KiB
Python
96 lines
3.2 KiB
Python
from django.conf.urls.defaults import patterns, url, include
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class ApiEntry(object):
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"""
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Hold information about a Resource in the api
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"""
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def __init__(self, resource, view, name, namespace=None):
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self.resource, self.view, self.name = resource, view, name
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self.namespace = namespace is not None and namespace or ''
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def get_urls(self):
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"""
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Create the URLs corresponding to this view.
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"""
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from djangorestframework.mixins import ListModelMixin, InstanceMixin
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if self.namespace == '':
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namespaced_name = self.name
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else:
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namespaced_name = '%s/%s' % (self.namespace, self.name)
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if issubclass(self.view, ListModelMixin):
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urlpatterns = patterns('',
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url(r'^%s/$' % (namespaced_name),
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self.view.as_view(resource=self.resource),
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name=self.name,
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)
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)
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elif issubclass(self.view, InstanceMixin):
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urlpatterns = patterns('',
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url(r'^%s/(?P<pk>[0-9a-zA-Z]+)/$' % (namespaced_name),
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self.view.as_view(resource=self.resource),
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name=self.name + '_change',
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)
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)
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return urlpatterns
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def urls(self):
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return self.get_urls(), 'api', self.namespace
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urls = property(urls)
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class DjangoRestFrameworkApi(object):
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app_name = 'api'
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namespace = 'api'
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def __init__(self, *args, **kwargs):
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self._registry = {}
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super(DjangoRestFrameworkApi, self).__init__(*args, **kwargs)
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def register(self, view, resource, namespace=None, name=None):
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"""
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Register a resource and a view into the API, optionally giving an
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override for the resource's name and a namespace for the URLs.
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"""
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if name is None:
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if hasattr(resource, 'model'):
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# Use the model's name as the resource_name
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name = resource.model.__name__.lower()
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else:
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# Use the Resource's name as the resource_name
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name = resource.__name__.lower()
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resource.api_name = name
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if namespace not in self._registry:
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self._registry[namespace] = {}
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if name not in self._registry[namespace]:
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self._registry[namespace][name] = []
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api_entry = ApiEntry(resource, view, name, namespace)
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self._registry[namespace][name].append(api_entry)
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@property
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def urls(self):
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return self.get_urls(), self.app_name, self.namespace
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def get_urls(self):
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"""
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Return all of the urls for this API
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"""
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# Site-wide views.
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urlpatterns = patterns('',)
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# Add in each resource's views.
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for namespace in self._registry.keys():
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for resource_name in self._registry[namespace].keys():
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for api_entry in self._registry[namespace][resource_name]:
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urlpatterns += patterns('',
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url(r'^', include(api_entry.urls))
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)
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return urlpatterns
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