* Add functions for Levenshtein distance alignment

This commit is contained in:
Matthew Honnibal 2015-05-24 21:50:48 +02:00
parent 744f06abf5
commit 3593babd35

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@ -2,11 +2,92 @@ import numpy
import codecs
import json
import random
from .munge.alignment import align
import re
from libc.string cimport memset
def align(cand_words, gold_words):
cost, edit_path = _min_edit_path(cand_words, gold_words)
alignment = []
i_of_gold = 0
for move in edit_path:
if move == 'M':
alignment.append(i_of_gold)
i_of_gold += 1
elif move == 'S':
alignment.append(None)
i_of_gold += 1
elif move == 'D':
alignment.append(None)
elif move == 'I':
i_of_gold += 1
else:
raise Exception(move)
return alignment
punct_re = re.compile(r'\W')
def _min_edit_path(cand_words, gold_words):
cdef:
Pool mem
int i, j, n_cand, n_gold
int* curr_costs
int* prev_costs
# TODO: Fix this --- just do it properly, make the full edit matrix and
# then walk back over it...
mem = Pool()
# Preprocess inputs
cand_words = [punct_re.sub('', w) for w in cand_words]
gold_words = [punct_re.sub('', w) for w in gold_words]
n_cand = len(cand_words)
n_gold = len(gold_words)
# Levenshtein distance, except we need the history, and we may want different
# costs.
# Mark operations with a string, and score the history using _edit_cost.
previous_row = []
prev_costs = <int*>mem.alloc(n_gold + 1, sizeof(int))
curr_costs = <int*>mem.alloc(n_gold + 1, sizeof(int))
for i in range(n_gold + 1):
cell = ''
for j in range(i):
cell += 'I'
previous_row.append('I' * i)
prev_costs[i] = i
for i, cand in enumerate(cand_words):
current_row = ['D' * (i + 1)]
curr_costs[0] = i+1
for j, gold in enumerate(gold_words):
if gold.lower() == cand.lower():
s_cost = prev_costs[j]
i_cost = curr_costs[j] + 1
d_cost = prev_costs[j + 1] + 1
else:
s_cost = prev_costs[j] + 1
i_cost = curr_costs[j] + 1
d_cost = prev_costs[j + 1] + (1 if cand else 0)
if s_cost <= i_cost and s_cost <= d_cost:
best_cost = s_cost
best_hist = previous_row[j] + ('M' if gold == cand else 'S')
elif i_cost <= s_cost and i_cost <= d_cost:
best_cost = i_cost
best_hist = current_row[j] + 'I'
else:
best_cost = d_cost
best_hist = previous_row[j + 1] + 'D'
current_row.append(best_hist)
curr_costs[j+1] = best_cost
previous_row = current_row
for j in range(len(gold_words) + 1):
prev_costs[j] = curr_costs[j]
curr_costs[j] = 0
return prev_costs[n_gold], previous_row[-1]
def read_json_file(loc):
paragraphs = []
for doc in json.load(open(loc)):