Merge branch 'master' into spacy.io

This commit is contained in:
Ines Montani 2019-07-17 15:35:34 +02:00
commit 4c863aeb06
10 changed files with 201 additions and 35 deletions

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@ -67,7 +67,7 @@ valuable if it's shared publicly, so that more people can benefit from it.
- Non-destructive **tokenization**
- **Named entity** recognition
- Support for **49+ languages**
- Support for **50+ languages**
- Pre-trained [statistical models](https://spacy.io/models) and word vectors
- State-of-the-art speed
- Easy **deep learning** integration

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@ -70,15 +70,33 @@ def merge_sents(sents):
return [(m_deps, m_brackets)]
def align(cand_words, gold_words):
if cand_words == gold_words:
alignment = numpy.arange(len(cand_words))
def align(tokens_a, tokens_b):
"""Calculate alignment tables between two tokenizations, using the Levenshtein
algorithm. The alignment is case-insensitive.
tokens_a (List[str]): The candidate tokenization.
tokens_b (List[str]): The reference tokenization.
RETURNS: (tuple): A 5-tuple consisting of the following information:
* cost (int): The number of misaligned tokens.
* a2b (List[int]): Mapping of indices in `tokens_a` to indices in `tokens_b`.
For instance, if `a2b[4] == 6`, that means that `tokens_a[4]` aligns
to `tokens_b[6]`. If there's no one-to-one alignment for a token,
it has the value -1.
* b2a (List[int]): The same as `a2b`, but mapping the other direction.
* a2b_multi (Dict[int, int]): A dictionary mapping indices in `tokens_a`
to indices in `tokens_b`, where multiple tokens of `tokens_a` align to
the same token of `tokens_b`.
* b2a_multi (Dict[int, int]): As with `a2b_multi`, but mapping the other
direction.
"""
if tokens_a == tokens_b:
alignment = numpy.arange(len(tokens_a))
return 0, alignment, alignment, {}, {}
cand_words = [w.replace(" ", "").lower() for w in cand_words]
gold_words = [w.replace(" ", "").lower() for w in gold_words]
cost, i2j, j2i, matrix = _align.align(cand_words, gold_words)
i2j_multi, j2i_multi = _align.multi_align(i2j, j2i, [len(w) for w in cand_words],
[len(w) for w in gold_words])
tokens_a = [w.replace(" ", "").lower() for w in tokens_a]
tokens_b = [w.replace(" ", "").lower() for w in tokens_b]
cost, i2j, j2i, matrix = _align.align(tokens_a, tokens_b)
i2j_multi, j2i_multi = _align.multi_align(i2j, j2i, [len(w) for w in tokens_a],
[len(w) for w in tokens_b])
for i, j in list(i2j_multi.items()):
if i2j_multi.get(i+1) != j and i2j_multi.get(i-1) != j:
i2j[i] = j

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@ -1,7 +1,6 @@
# coding: utf8
from __future__ import unicode_literals
import pytest
import spacy
from spacy.util import minibatch, compounding
@ -9,27 +8,25 @@ from spacy.util import minibatch, compounding
def test_issue3611():
""" Test whether adding n-grams in the textcat works even when n > token length of some docs """
unique_classes = ["offensive", "inoffensive"]
x_train = ["This is an offensive text",
x_train = [
"This is an offensive text",
"This is the second offensive text",
"inoff"]
"inoff",
]
y_train = ["offensive", "offensive", "inoffensive"]
# preparing the data
pos_cats = list()
for train_instance in y_train:
pos_cats.append({label: label == train_instance for label in unique_classes})
train_data = list(zip(x_train, [{'cats': cats} for cats in pos_cats]))
train_data = list(zip(x_train, [{"cats": cats} for cats in pos_cats]))
# set up the spacy model with a text categorizer component
nlp = spacy.blank('en')
nlp = spacy.blank("en")
textcat = nlp.create_pipe(
"textcat",
config={
"exclusive_classes": True,
"architecture": "bow",
"ngram_size": 2
}
config={"exclusive_classes": True, "architecture": "bow", "ngram_size": 2},
)
for label in unique_classes:
@ -37,7 +34,7 @@ def test_issue3611():
nlp.add_pipe(textcat, last=True)
# training the network
other_pipes = [pipe for pipe in nlp.pipe_names if pipe != 'textcat']
other_pipes = [pipe for pipe in nlp.pipe_names if pipe != "textcat"]
with nlp.disable_pipes(*other_pipes):
optimizer = nlp.begin_training()
for i in range(3):
@ -46,6 +43,10 @@ def test_issue3611():
for batch in batches:
texts, annotations = zip(*batch)
nlp.update(docs=texts, golds=annotations, sgd=optimizer, drop=0.1, losses=losses)
nlp.update(
docs=texts,
golds=annotations,
sgd=optimizer,
drop=0.1,
losses=losses,
)

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@ -3,8 +3,10 @@ from __future__ import unicode_literals
from spacy.lang.hi import Hindi
def test_issue3625():
"""Test that default punctuation rules applies to hindi unicode characters"""
nlp = Hindi()
doc = nlp(u"hi. how हुए. होटल, होटल")
assert [token.text for token in doc] == ['hi', '.', 'how', 'हुए', '.', 'होटल', ',', 'होटल']
doc = nlp("hi. how हुए. होटल, होटल")
expected = ["hi", ".", "how", "हुए", ".", "होटल", ",", "होटल"]
assert [token.text for token in doc] == expected

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@ -1,7 +1,6 @@
# coding: utf8
from __future__ import unicode_literals
import pytest
from spacy.matcher import Matcher
from spacy.tokens import Doc

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@ -2,7 +2,6 @@
from __future__ import unicode_literals
import pytest
from spacy.attrs import IS_ALPHA
from spacy.lang.en import English
@ -10,11 +9,11 @@ from spacy.lang.en import English
@pytest.mark.parametrize(
"sentence",
[
'The story was to the effect that a young American student recently called on Professor Christlieb with a letter of introduction.',
'The next month Barry Siddall joined Stoke City on a free transfer, after Chris Pearce had established himself as the Vale\'s #1.',
'The next month Barry Siddall joined Stoke City on a free transfer, after Chris Pearce had established himself as the Vale\'s number one',
'Indeed, making the one who remains do all the work has installed him into a position of such insolent tyranny, it will take a month at least to reduce him to his proper proportions.',
"It was a missed assignment, but it shouldn't have resulted in a turnover ..."
"The story was to the effect that a young American student recently called on Professor Christlieb with a letter of introduction.",
"The next month Barry Siddall joined Stoke City on a free transfer, after Chris Pearce had established himself as the Vale's #1.",
"The next month Barry Siddall joined Stoke City on a free transfer, after Chris Pearce had established himself as the Vale's number one",
"Indeed, making the one who remains do all the work has installed him into a position of such insolent tyranny, it will take a month at least to reduce him to his proper proportions.",
"It was a missed assignment, but it shouldn't have resulted in a turnover ...",
],
)
def test_issue3869(sentence):
@ -27,5 +26,3 @@ def test_issue3869(sentence):
count += token.is_alpha
assert count == doc.count_by(IS_ALPHA).get(1, 0)

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@ -0,0 +1,22 @@
# coding: utf8
from __future__ import unicode_literals
import pytest
from spacy.matcher import Matcher
from spacy.tokens import Doc
@pytest.mark.xfail
def test_issue3951(en_vocab):
"""Test that combinations of optional rules are matched correctly."""
matcher = Matcher(en_vocab)
pattern = [
{"LOWER": "hello"},
{"LOWER": "this", "OP": "?"},
{"OP": "?"},
{"LOWER": "world"},
]
matcher.add("TEST", None, pattern)
doc = Doc(en_vocab, words=["Hello", "my", "new", "world"])
matches = matcher(doc)
assert len(matches) == 0

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@ -0,0 +1,18 @@
# coding: utf8
from __future__ import unicode_literals
import pytest
from spacy.matcher import PhraseMatcher
from spacy.tokens import Doc
@pytest.mark.xfail
def test_issue3972(en_vocab):
"""Test that the PhraseMatcher returns duplicates for duplicate match IDs.
"""
matcher = PhraseMatcher(en_vocab)
matcher.add("A", None, Doc(en_vocab, words=["New", "York"]))
matcher.add("B", None, Doc(en_vocab, words=["New", "York"]))
doc = Doc(en_vocab, words=["I", "live", "in", "New", "York"])
matches = matcher(doc)
assert len(matches) == 2

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@ -76,6 +76,50 @@ Convert a list of Doc objects into the
| `id` | int | ID to assign to the JSON. Defaults to `0`. |
| **RETURNS** | list | The data in spaCy's JSON format. |
### gold.align {#align tag="function"}
Calculate alignment tables between two tokenizations, using the Levenshtein
algorithm. The alignment is case-insensitive.
> #### Example
>
> ```python
> from spacy.gold import align
>
> bert_tokens = ["obama", "'", "s", "podcast"]
> spacy_tokens = ["obama", "'s", "podcast"]
> alignment = align(bert_tokens, spacy_tokens)
> cost, a2b, b2a, a2b_multi, b2a_multi = alignment
> ```
| Name | Type | Description |
| ----------- | ----- | -------------------------------------------------------------------------- |
| `tokens_a` | list | String values of candidate tokens to align. |
| `tokens_b` | list | String values of reference tokens to align. |
| **RETURNS** | tuple | A `(cost, a2b, b2a, a2b_multi, b2a_multi)` tuple describing the alignment. |
The returned tuple contains the following alignment information:
> #### Example
>
> ```python
> a2b = array([0, -1, -1, 2])
> b2a = array([0, 2, 3])
> a2b_multi = {1: 1, 2: 1}
> b2a_multi = {}
> ```
>
> If `a2b[3] == 2`, that means that `tokens_a[3]` aligns to `tokens_b[2]`. If
> there's no one-to-one alignment for a token, it has the value `-1`.
| Name | Type | Description |
| ----------- | -------------------------------------- | ----------------------------------------------------------------------------------------------------------------------------------------------- |
| `cost` | int | The number of misaligned tokens. |
| `a2b` | `numpy.ndarray[ndim=1, dtype='int32']` | One-to-one mappings of indices in `tokens_a` to indices in `tokens_b`. |
| `b2a` | `numpy.ndarray[ndim=1, dtype='int32']` | One-to-one mappings of indices in `tokens_b` to indices in `tokens_a`. |
| `a2b_multi` | dict | A dictionary mapping indices in `tokens_a` to indices in `tokens_b`, where multiple tokens of `tokens_a` align to the same token of `tokens_b`. |
| `b2a_multi` | dict | A dictionary mapping indices in `tokens_b` to indices in `tokens_a`, where multiple tokens of `tokens_b` align to the same token of `tokens_a`. |
### gold.biluo_tags_from_offsets {#biluo_tags_from_offsets tag="function"}
Encode labelled spans into per-token tags, using the

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@ -963,6 +963,71 @@ Once you have a [`Doc`](/api/doc) object, you can write to its attributes to set
the part-of-speech tags, syntactic dependencies, named entities and other
attributes. For details, see the respective usage pages.
### Aligning tokenization {#aligning-tokenization}
spaCy's tokenization is non-destructive and uses language-specific rules
optimized for compatibility with treebank annotations. Other tools and resources
can sometimes tokenize things differently for example, `"I'm"`
`["I", "'", "m"]` instead of `["I", "'m"]`.
In cases like that, you often want to align the tokenization so that you can
merge annotations from different sources together, or take vectors predicted by
a [pre-trained BERT model](https://github.com/huggingface/pytorch-transformers)
and apply them to spaCy tokens. spaCy's [`gold.align`](/api/goldparse#align)
helper returns a `(cost, a2b, b2a, a2b_multi, b2a_multi)` tuple describing the
number of misaligned tokens, the one-to-one mappings of token indices in both
directions and the indices where multiple tokens align to one single token.
> #### ✏️ Things to try
>
> 1. Change the capitalization in one of the token lists for example,
> `"obama"` to `"Obama"`. You'll see that the alignment is case-insensitive.
> 2. Change `"podcasts"` in `other_tokens` to `"pod", "casts"`. You should see
> that there are now 4 misaligned tokens and that the new many-to-one mapping
> is reflected in `a2b_multi`.
> 3. Make `other_tokens` and `spacy_tokens` identical. You'll see that the
> `cost` is `0` and all corresponding mappings are also identical.
```python
### {executable="true"}
from spacy.gold import align
other_tokens = ["i", "listened", "to", "obama", "'", "s", "podcasts", "."]
spacy_tokens = ["i", "listened", "to", "obama", "'s", "podcasts", "."]
cost, a2b, b2a, a2b_multi, b2a_multi = align(other_tokens, spacy_tokens)
print("Misaligned tokens:", cost) # 2
print("One-to-one mappings a -> b", a2b) # array([0, 1, 2, 3, -1, -1, 5, 6])
print("One-to-one mappings b -> a", b2a) # array([0, 1, 2, 3, 5, 6, 7])
print("Many-to-one mappings a -> b", a2b_multi) # {4: 4, 5: 4}
print("Many-to-one mappings b-> a", b2a_multi) # {}
```
Here are some insights from the alignment information generated in the example
above:
- Two tokens are misaligned.
- The one-to-one mappings for the first four tokens are identical, which means
they map to each other. This makes sense because they're also identical in the
input: `"i"`, `"listened"`, `"to"` and `"obama"`.
- The index mapped to `a2b[6]` is `5`, which means that `other_tokens[6]`
(`"podcasts"`) aligns to `spacy_tokens[6]` (also `"podcasts"`).
- `a2b[4]` is `-1`, which means that there is no one-to-one alignment for the
token at `other_tokens[5]`. The token `"'"` doesn't exist on its own in
`spacy_tokens`. The same goes for `a2b[5]` and `other_tokens[5]`, i.e. `"s"`.
- The dictionary `a2b_multi` shows that both tokens 4 and 5 of `other_tokens`
(`"'"` and `"s"`) align to token 4 of `spacy_tokens` (`"'s"`).
- The dictionary `b2a_multi` shows that there are no tokens in `spacy_tokens`
that map to multiple tokens in `other_tokens`.
<Infobox title="Important note" variant="warning">
The current implementation of the alignment algorithm assumes that both
tokenizations add up to the same string. For example, you'll be able to align
`["I", "'", "m"]` and `["I", "'m"]`, which both add up to `"I'm"`, but not
`["I", "'m"]` and `["I", "am"]`.
</Infobox>
## Merging and splitting {#retokenization new="2.1"}
The [`Doc.retokenize`](/api/doc#retokenize) context manager lets you merge and