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Merge branch 'master' into spacy.io
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4f0304a79c
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@ -1011,9 +1011,9 @@ above:
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they map to each other. This makes sense because they're also identical in the
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they map to each other. This makes sense because they're also identical in the
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input: `"i"`, `"listened"`, `"to"` and `"obama"`.
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input: `"i"`, `"listened"`, `"to"` and `"obama"`.
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- The index mapped to `a2b[6]` is `5`, which means that `other_tokens[6]`
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- The index mapped to `a2b[6]` is `5`, which means that `other_tokens[6]`
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(`"podcasts"`) aligns to `spacy_tokens[6]` (also `"podcasts"`).
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(`"podcasts"`) aligns to `spacy_tokens[5]` (also `"podcasts"`).
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- `a2b[4]` is `-1`, which means that there is no one-to-one alignment for the
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- `a2b[4]` is `-1`, which means that there is no one-to-one alignment for the
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token at `other_tokens[5]`. The token `"'"` doesn't exist on its own in
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token at `other_tokens[4]`. The token `"'"` doesn't exist on its own in
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`spacy_tokens`. The same goes for `a2b[5]` and `other_tokens[5]`, i.e. `"s"`.
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`spacy_tokens`. The same goes for `a2b[5]` and `other_tokens[5]`, i.e. `"s"`.
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- The dictionary `a2b_multi` shows that both tokens 4 and 5 of `other_tokens`
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- The dictionary `a2b_multi` shows that both tokens 4 and 5 of `other_tokens`
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(`"'"` and `"s"`) align to token 4 of `spacy_tokens` (`"'s"`).
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(`"'"` and `"s"`) align to token 4 of `spacy_tokens` (`"'s"`).
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