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Initialize all values in a2b/b2a in new align (#5063)

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adrianeboyd 2020-02-27 18:43:00 +01:00 committed by GitHub
parent b4e0d2bf50
commit 65d7bab10f
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1 changed files with 2 additions and 1 deletions
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spacy/gold.pyx
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@ -151,6 +151,8 @@ def align(tokens_a, tokens_b):
cost = 0 cost = 0
a2b = numpy.empty(len(tokens_a), dtype="i") a2b = numpy.empty(len(tokens_a), dtype="i")
b2a = numpy.empty(len(tokens_b), dtype="i") b2a = numpy.empty(len(tokens_b), dtype="i")
a2b.fill(-1)
b2a.fill(-1)
a2b_multi = {} a2b_multi = {}
b2a_multi = {} b2a_multi = {}
i = 0 i = 0
@ -160,7 +162,6 @@ def align(tokens_a, tokens_b):
while i < len(tokens_a) and j < len(tokens_b): while i < len(tokens_a) and j < len(tokens_b):
a = tokens_a[i][offset_a:] a = tokens_a[i][offset_a:]
b = tokens_b[j][offset_b:] b = tokens_b[j][offset_b:]
a2b[i] = b2a[j] = -1
if a == b: if a == b:
if offset_a == offset_b == 0: if offset_a == offset_b == 0:
a2b[i] = j a2b[i] = j