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4448680750
* When checking for token alignments, check not only that the tokens are identical but that the character positions are both at the start of a token. It's possible for the tokens to be identical even though the two tokens aren't aligned one-to-one in a case like `["a'", "''"]` vs. `["a", "''", "'"]`, where the middle tokens are identical but should not be aligned on the token level at character position 2 since it's the start of one token but the middle of another. * Use the lowercased version of the token texts to create the character-to-token alignment because lowercasing can change the string length (e.g., for `İ`, see the not-a-bug bug report: https://bugs.python.org/issue34723)
73 lines
3.1 KiB
Cython
73 lines
3.1 KiB
Cython
from typing import List, Tuple
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from itertools import chain
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import re
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from ..errors import Errors
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def get_alignments(A: List[str], B: List[str]) -> Tuple[List[List[int]], List[List[int]]]:
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# Create character-to-token mappings
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char_to_token_a = tuple(chain(*((i,) * len(x.lower()) for i, x in enumerate(A))))
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char_to_token_b = tuple(chain(*((i,) * len(x.lower()) for i, x in enumerate(B))))
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str_a = "".join(A).lower()
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str_b = "".join(B).lower()
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cdef int len_str_a = len(str_a)
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cdef int len_str_b = len(str_b)
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# Check that the two texts only differ in whitespace and capitalization
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if re.sub(r"\s+", "", str_a) != re.sub(r"\s+", "", str_b) or \
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len_str_a != len(char_to_token_a) or \
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len_str_b != len(char_to_token_b):
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raise ValueError(Errors.E949.format(x=str(A[:10]), y=str(B[:10])))
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cdef int char_idx_a = 0
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cdef int char_idx_b = 0
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cdef int token_idx_a = 0
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cdef int token_idx_b = 0
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cdef int prev_token_idx_a = -1
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cdef int prev_token_idx_b = -1
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a2b = []
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b2a = []
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while char_idx_a < len_str_a and char_idx_b < len_str_b:
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# Find the current token position from the character position
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token_idx_a = char_to_token_a[char_idx_a]
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token_idx_b = char_to_token_b[char_idx_b]
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# Add a set for the next token if a token boundary has been crossed
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if prev_token_idx_a != token_idx_a:
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a2b.append(set())
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if prev_token_idx_b != token_idx_b:
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b2a.append(set())
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# Process the alignment at the current position
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if A[token_idx_a] == B[token_idx_b] and \
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(char_idx_a == 0 or \
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char_to_token_a[char_idx_a - 1] < token_idx_a) and \
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(char_idx_b == 0 or \
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char_to_token_b[char_idx_b - 1] < token_idx_b):
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# Current tokens are identical and both character offsets are the
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# start of a token (either at the beginning of the document or the
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# previous character belongs to a different token)
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a2b[-1].add(token_idx_b)
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b2a[-1].add(token_idx_a)
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char_idx_a += len(A[token_idx_a])
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char_idx_b += len(B[token_idx_b])
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elif str_a[char_idx_a] == str_b[char_idx_b]:
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# Current chars are identical
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a2b[-1].add(token_idx_b)
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b2a[-1].add(token_idx_a)
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char_idx_a += 1
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char_idx_b += 1
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elif str_a[char_idx_a].isspace():
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# Skip unaligned whitespace char in A
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char_idx_a += 1
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elif str_b[char_idx_b].isspace():
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# Skip unaligned whitespace char in B
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char_idx_b += 1
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else:
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# This should never happen
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raise ValueError(Errors.E949.format(x=str(A[:10]), y=str(B[:10])))
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prev_token_idx_a = token_idx_a
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prev_token_idx_b = token_idx_b
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# Process unaligned trailing whitespace
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a2b.extend([set()] * len(set(char_to_token_a[char_idx_a:])))
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b2a.extend([set()] * len(set(char_to_token_b[char_idx_b:])))
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# Return values as sorted lists per token position
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return [sorted(x) for x in a2b], [sorted(x) for x in b2a]
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