spaCy/spacy/pipeline/_parser_internals/stateclass.pyx
Matthew Honnibal c1bf3a5602
Fix significant performance bug in parser training (#6010)
The parser training makes use of a trick for long documents, where we
use the oracle to cut up the document into sections, so that we can have
batch items in the middle of a document. For instance, if we have one
document of 600 words, we might make 6 states, starting at words 0, 100,
200, 300, 400 and 500.

The problem is for v3, I screwed this up and didn't stop parsing! So
instead of a batch of [100, 100, 100, 100, 100, 100], we'd have a batch
of [600, 500, 400, 300, 200, 100]. Oops.

The implementation here could probably be improved, it's annoying to
have this extra variable in the state. But this'll do.

This makes the v3 parser training 5-10 times faster, depending on document
lengths. This problem wasn't in v2.
2020-09-02 12:57:13 +02:00

59 lines
1.5 KiB
Cython

# cython: infer_types=True
import numpy
from ...tokens.doc cimport Doc
cdef class StateClass:
def __init__(self, Doc doc=None, int offset=0):
cdef Pool mem = Pool()
self.mem = mem
self._borrowed = 0
if doc is not None:
self.c = new StateC(doc.c, doc.length)
self.c.offset = offset
def __dealloc__(self):
if self._borrowed != 1:
del self.c
@property
def stack(self):
return {self.S(i) for i in range(self.c._s_i)}
@property
def queue(self):
return {self.B(i) for i in range(self.c.buffer_length())}
@property
def token_vector_lenth(self):
return self.doc.tensor.shape[1]
@property
def history(self):
hist = numpy.ndarray((8,), dtype='i')
for i in range(8):
hist[i] = self.c.get_hist(i+1)
return hist
@property
def n_pushes(self):
return self.c.n_pushes
def is_final(self):
return self.c.is_final()
def copy(self):
cdef StateClass new_state = StateClass.init(self.c._sent, self.c.length)
new_state.c.clone(self.c)
return new_state
def print_state(self, words):
words = list(words) + ['_']
top = f"{words[self.S(0)]}_{self.S_(0).head}"
second = f"{words[self.S(1)]}_{self.S_(1).head}"
third = f"{words[self.S(2)]}_{self.S_(2).head}"
n0 = words[self.B(0)]
n1 = words[self.B(1)]
return ' '.join((third, second, top, '|', n0, n1))