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fix: only one query for 1o1 relation
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@ -299,33 +299,16 @@ def convert_onetoone_field_to_djangomodel(field, registry=None):
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# the default Django resolver
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return fk_obj
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object_pk = resolver(root, info, **args).pk
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instance_from_get_node = _type.get_node(info, object_pk)
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if instance_from_get_node is None:
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# no instance to return
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return
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elif (
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isinstance(resolver, partial)
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and resolver.func is get_default_resolver()
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):
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return instance_from_get_node
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elif resolver is not get_default_resolver():
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# Default resolver is overridden
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# For optimization, add the instance to the resolver
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field_name = to_snake_case(info.field_name)
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setattr(root, field_name, instance_from_get_node)
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# Explanation:
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# previously, _type.get_node` is called which results in at least one hit to the database.
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# But, if we did not pass the instance to the root, calling the resolver will result in
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# another call to get the instance which results in at least two database queries in total
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# to resolve this node only.
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# That's why the value of the object is set in the root so when the object is accessed
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# in the resolver (root.field_name) it does not access the database unless queried explicitly.
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fk_obj = resolver(root, info, **args)
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return fk_obj
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else:
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return instance_from_get_node
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field_name = to_snake_case(info.field_name)
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reversed_field_name = root.__class__._meta.get_field(
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field_name
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).remote_field.name
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return _type.get_queryset(
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_type._meta.model.objects.filter(
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**{reversed_field_name: root.pk}
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),
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info,
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).get()
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return custom_resolver
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