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Allow DjangoObjectType to have default _meta

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mongkok 2018-01-22 01:03:52 +05:30
parent e05f069b3b
commit 167d0a3964
1 changed files with 4 additions and 2 deletions
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6
graphene_django/types.py
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@ -45,7 +45,7 @@ class DjangoObjectType(ObjectType):
@classmethod @classmethod
def __init_subclass_with_meta__(cls, model=None, registry=None, skip_registry=False, def __init_subclass_with_meta__(cls, model=None, registry=None, skip_registry=False,
only_fields=(), exclude_fields=(), filter_fields=None, connection=None, only_fields=(), exclude_fields=(), filter_fields=None, connection=None,
connection_class=None, use_connection=None, interfaces=(), **options): connection_class=None, use_connection=None, interfaces=(), _meta=None, **options):
assert is_valid_django_model(model), ( assert is_valid_django_model(model), (
'You need to pass a valid Django Model in {}.Meta, received "{}".' 'You need to pass a valid Django Model in {}.Meta, received "{}".'
).format(cls.__name__, model) ).format(cls.__name__, model)
@ -82,7 +82,9 @@ class DjangoObjectType(ObjectType):
"The connection must be a Connection. Received {}" "The connection must be a Connection. Received {}"
).format(connection.__name__) ).format(connection.__name__)
_meta = DjangoObjectTypeOptions(cls) if not _meta:
_meta = DjangoObjectTypeOptions(cls)
_meta.model = model _meta.model = model
_meta.registry = registry _meta.registry = registry
_meta.filter_fields = filter_fields _meta.filter_fields = filter_fields