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58 lines
1.7 KiB
Python
58 lines
1.7 KiB
Python
#!/usr/bin/env python
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"""
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Copyright (c) 2006-2012 sqlmap developers (http://sqlmap.org/)
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See the file 'doc/COPYING' for copying permission
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"""
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import binascii
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import re
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from lib.core.common import isDBMSVersionAtLeast
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from lib.core.exception import sqlmapSyntaxException
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from plugins.generic.syntax import Syntax as GenericSyntax
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class Syntax(GenericSyntax):
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def __init__(self):
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GenericSyntax.__init__(self)
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@staticmethod
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def unescape(expression, quote=True):
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unescaped = expression
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if isDBMSVersionAtLeast('3'):
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if quote:
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for item in re.findall(r"'[^']+'", expression, re.S):
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unescaped = unescaped.replace(item, "X'%s'" % binascii.hexlify(item.strip("'")))
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else:
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unescaped = "X'%s'" % binascii.hexlify(expression)
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return unescaped
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@staticmethod
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def escape(expression):
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# Example on SQLite 3, not supported on SQLite 2:
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# select X'48'||X'656c6c6f20576f726c6400'; -- Hello World
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while True:
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index = expression.find("X'")
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if index == -1:
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break
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firstIndex = index
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index = expression[firstIndex+2:].find("'")
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if index == -1:
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raise sqlmapSyntaxException, "Unenclosed ' in '%s'" % expression
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lastIndex = firstIndex + index + 3
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old = expression[firstIndex:lastIndex]
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oldUpper = old.upper()
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oldUpper = oldUpper.replace("X'", "").replace("'", "")
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for i in xrange(len(oldUpper)/2):
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char = oldUpper[i*2:i*2+2]
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escaped = "'%s'" % chr(int(char, 16))
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expression = expression.replace(old, escaped)
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return expression
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